Fred, that no longer computes.
You said: 'If a scope with fixed parallax adjustment was set for zero error at 200 yards, then the parallax error would be on opposite sides of the set plane but equal size at 300 or 100 yards and also equal but twice that size at 400 or 50 yards.'
Using you power of two progression,I believe that is analogous to a logarithmic scale, base 2,) setting up for zero error at 200 yards would mean the parallax error would be the same magnitude, simply opposite at 100 and 400. 100 yards is half the distance of 200 and 200 is half the distance of 400.) It would then be that at 50 yards,one quarter the distance from 200), the magnitude of the error would be the same as at 800 yards,of which 200 is one quarter.)
Certainly on my AOs, the difference between 300 and 1000 yards setting is minuscule compared to the difference between 100 and 300. Closer than that is an even digger displacement.
Help me understand your numbers, please.
You said: 'If a scope with fixed parallax adjustment was set for zero error at 200 yards, then the parallax error would be on opposite sides of the set plane but equal size at 300 or 100 yards and also equal but twice that size at 400 or 50 yards.'
Using you power of two progression,I believe that is analogous to a logarithmic scale, base 2,) setting up for zero error at 200 yards would mean the parallax error would be the same magnitude, simply opposite at 100 and 400. 100 yards is half the distance of 200 and 200 is half the distance of 400.) It would then be that at 50 yards,one quarter the distance from 200), the magnitude of the error would be the same as at 800 yards,of which 200 is one quarter.)
Certainly on my AOs, the difference between 300 and 1000 yards setting is minuscule compared to the difference between 100 and 300. Closer than that is an even digger displacement.
Help me understand your numbers, please.