Ok. A little physics for the layman.
Energy is conserved. So all the energy in the recoil goes into your rifle. This energy is dissipated many ways:
1. your shoulder
2. moving the rifle. the heavier the rifle, the more energy it absorbs moving it.
3. compressing the recoil pad on the stock.
4. any bending of any rifle components. I remember a thread here recently about how much a rear-lugged bolt compresses. that absorbs energy.
5. other minor losses.
Most of the energy goes into the first 3. Your rifle is accelerated by the round and stopped by your shoulder. This is a very elastic collision (when you hear "elastic collision" think of dropping a ball of modeling clay and it hits the floor and sticks). In an inelastic collision, all the energy is absorbed by the collision over a fairly long distance of travel. Lets say the modeling class makes a flat spot about 1/2" deep so the deceleration takes place over 1/2". Very gentle from a physics standpoint.
Elastic collision: Now drop a ball bearing. the steel surface of a ball bearing compresses maybe .0001" and the energy goes right back into the ball bearing causing it to rocket back up. This is a mostly elastic collision. it is very violent and puts almost all the energy back into the ball bearing.
We can say from a practical point of view that there is no such thing as a perfectly elastic collision since 100% of the energy would be returned and the velocity would reverse instantaneously. to change velocity instantaneously, the acceleration must be infinity.
I make that point on purpose. the more elastic the collision, the shorter the time and the shorter the travel of the moving object being stopped the higher the accelerations. (quick review, force=Massxacceleration. So when you hear the word "acceleration" you can just think "force").
So the shorter the allowed travel of the moving rifle, the more inelastic the collision, and the higher the acceleration. if you put a rigid rifle against a concrete wall and pull the trigger it would bouce forward. That should make intuitive sense to you. So the more you constrain a rifle, the less you let it move in recoil, the higher the g-forces experienced in the stop. And we attach the scope very rigidly to the rifle so it feels about the same forces as the rifle.
It was suggested above that using a double braced scope (for air rifles) will solve the problem. I don't know if that will be adequate or not. But these increased forces from stopping are the forces that the air gun scope is braced for.
So a heavy gun doesn't have this problem because the energy is mostly absorbed trying to accelerate the gun.
--Jerry