Not wrong good catch, my mistake, on the rotary switch pin 1 should be to the sub board 0v and not connect to the PS pin 11, so I see why there might be some confusion.
When the switch is in position 1 the 5v ref voltage has to pass thru all the resistors to the 0v, so the voltage output for the center tap is lowered with increasing resistance. Pin 7 is 0 resistance so the full 5v is passed on to the center tap.
Having a near 2v switch position (approx. 6.5A) is useful for smaller thinner cases in my opinion.
You could probably get away with fewer steps, 7 steps is more than enough in the real world, 4 or 5 would cover everything from 22 hornet to 50 BMG, just set up the resistors on the switch to cover the entire range from 2.1v to 5.0v in even steps.
Attached is a spreadsheet to help calculate PS output for each resistor step and the resistor value needed. These are approximate values as the response is not perfectly linear but in reality they are pretty close, within +/- .1 A .
When the switch is in position 1 the 5v ref voltage has to pass thru all the resistors to the 0v, so the voltage output for the center tap is lowered with increasing resistance. Pin 7 is 0 resistance so the full 5v is passed on to the center tap.
Having a near 2v switch position (approx. 6.5A) is useful for smaller thinner cases in my opinion.
You could probably get away with fewer steps, 7 steps is more than enough in the real world, 4 or 5 would cover everything from 22 hornet to 50 BMG, just set up the resistors on the switch to cover the entire range from 2.1v to 5.0v in even steps.
Attached is a spreadsheet to help calculate PS output for each resistor step and the resistor value needed. These are approximate values as the response is not perfectly linear but in reality they are pretty close, within +/- .1 A .
Maybe this was the wrong word ;-)
At pg 19/#373 (att 1.jpg) there is the schematic with the hint to connect only to 7 of the power supply (without 11) - that's fine with me.
At pg 18/#345 (att 2.jpg) there is the schematic of the sub board.
Switch position "1" is connected via the black line to 0V of the 5V-LVR.
If I switch to position "1" 0V is connected to 7 (power supply - current limit control).
In this case the voltage is less than 2V and I'm not sure if this is right and what happen.
In your first idea pg15/#300 there is a resistor between the pot and 0V that is preventing that the voltage goes below 2V - that's fine with me, too.
Maybe I'm wrong and I haven't see this resistor in your schematic.