Fun with numbers!
-pat
So at its peak, this bullet was one third of a mile above the deck. At what point is the shooter figuring on the weather the bullet goes through "up there"?
Or is there something to the notion that we might just be winging it?
Fun with numbers!
-pat
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So taking the initial 14462 inches + 6240 inches gives you total 20,702 inches or 1725 feet or 575 yards of drop , with terminal velocity of 582 ft/s.
-pat
Well, well, that proves all those boxes of .22’s I got as a kid that said they would travel 2 miles must have been an understatement.
I have no doubt that he could,PROVIDING all there miles of the conditions are exact.The ballistics are impressive but could the shooter repeat this with a follow up shot? Just curious.
With my 6.5 creedmoor...if I do my part

I found an old program that will calculate out to the range he shot. Just for fun I ball parked the conditions and used the specs from a LeHigh .408 / 400 grain solid copper bullet at 3,160 fps. Also guessed at a 10" scope height and a 300 yard zero. Don't know how accurate this program is but at 5,280 yards a constant 1 mph breeze over the whole trajectory will push the bullet about 13.7' sideways causing you to miss the entire target, and the bullet drop is about 744 yards. If you could hold a 0.1" group at 100 yards, that would equate out to about 53" at the 53" square target.
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You're right. 1st mistake I ever made since being born! Well, almost! I'm blaming it on old age.Not sure about the rst of your numbers, but: "... If you could hold a 0.1" group at 100 yards, that would equate out to about 53" at the 53" square target...." is off by a factor of 10.
