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Coriolis and Ballistics-Flat Earthers Beware!

I was searching over previous posts about the Coriolis effect and saw people wondering how it works. I thought I would start a new thread and try to explain it a bit and how it applies to ballistics.

When we do physics of bullets, we use Newton's Law of Motion: F=ma or a=F/m. We find all of the forces that act on the bullet (F) and divide by the mass of the bullet (m) and get the acceleration of the bullet (a). We then integrate the acceleration to find the velocity and position of the bullet at any time.

Here is the problem, F=ma only works in what we call an "inertial" reference frame. That means that it is not accelerating. However, anyone that has driven around a curve knows that just going around a curve makes you feel acceleration. If the Earth is spinning about it's axis and the Earth is rotating around the sun and the solar system is spinning around the Milky Way, how the hell can we use it? Why can't we "feel" these accelerations?

The answer can be found in something called relative motion. If I want to use F=ma on Earth I have to correct it for these other motions or ignore them. When you apply these corrections you get three terms that pop out: Euler Acceleration, Centrifugal Acceleration, and Coriolis Acceleration. The math is what is called vector math but I can simplify it down to get rough estimates.

Euler Acceleration is based upon "angular acceleration" of how fast the spin is changing. Since the rotation of the Earth/Sun/Galaxy is pretty constant we can ignore it for ballistics.

Centrifugal Acceleration is a maximum of the spin squared times the radius. So for the Earth spins at 1 rotation per day with an average radius of 6378 km which gives us a centrifugal acceleration of 0.034 m/s^2 or about 0.003 "g" of acceleration. That is so small that it is not really noticeable in ballistics.

Coriolis though is based upon the speed of the object. It is 2 times the spin times the velocity. For throwing a ball it is not noticeable and for most engineering applications we can ignore Coriolis as well but with rifle bullets we start to get significant errors. The faster the bullet, the greater the error.

1719403551015.png
If you do the same math for Spin around the Sun/Galaxy you will see that they are insignificant.

So how do you correct for Coriolis? Well, it depends where you are on the Earth. The Earth spin vector points up from the North Pole. Part of it pushes the bullet to the right north of the Equator or to the left south of it. The other part of it either increases or decreases the apparent mass of bullet depending on if you are shooting east or west. This is the part that makes us launch rockets to the east as close to the equator as possible to reduce the apparent mass of the launch.

Given the uncertainty in calculating drop with drag, we often ignore the east/west apparent mass error but for long shots we need to include the small cross-range motion of the bullet. Most ballistic calculators include the cross range Coriolis correction. How do you know if yours does? If you need to enter in the Line of Fire (LOF) or direction that you are shooting and your latitude then your ballistic calculator can make the correction.

I hope this helps!

John Stutz, PhD
Aerospike Bullets, LLC
 
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I was searching over previous posts about the Coriolis effect and saw people wondering how it works. I thought I would start a new thread and try to explain it a bit and how it applies to ballistics.

When we do physics of bullets, we use Newton's Law of Motion: F=ma or a=F/m. We find all of the forces that act on the bullet (F) and divide by the mass of the bullet (m) and get the acceleration of the bullet (a). We then integrate the acceleration to find the velocity and position of the bullet at any time.

Here is the problem, F=ma only works in what we call an "inertial" reference frame. That means that it is not accelerating. However, anyone that has driven around a curve knows that just going around a curve makes you feel acceleration. If the Earth is spinning about it's axis and the Earth is rotating around the sun and the solar system is spinning around the Milky Way, how the hell can we use it? Why can't we "feel" these accelerations?

The answer can be found in something called relative motion. If I want to use F=ma on Earth I have to correct it for these other motions or ignore them. When you apply these corrections you get three terms that pop out: Euler Acceleration, Centrifugal Acceleration, and Coriolis Acceleration. The math is what is called vector math but I can simplify it down to get rough estimates.

Euler Acceleration is based upon "angular acceleration" of how fast the spin is changing. Since the rotation of the Earth/Sun/Galaxy is pretty constant we can ignore it for ballistics.

Centrifugal Acceleration is a maximum of the spin squared times the radius. So for the Earth spins at 1 rotation per day with an average radius of 6378 km which gives us a centrifugal acceleration of 0.034 m/s^2 or about 0.003 "g" of acceleration. That is so small that it is not really noticeable in ballistics.

Coriolis though is based upon the speed of the object. It is 2 times the spin times the velocity. For throwing a ball it is not noticeable and for most engineering applications we can ignore Coriolis as well but with rifle bullets we start to get significant errors. The faster the bullet, the greater the error.

View attachment 1566701
If you do the same math for Spin around the Sun/Galaxy you will see that they are insignificant.

So how do you correct for Coriolis? Well, it depends where you are on the Earth. The Earth spin vector points up from the North Pole. Part of it pushes the bullet to the right north of the Equator or to the left south of it. The other part of it either increases or decreases the apparent mass of bullet depending on if you are shooting east or west. This is the part that makes us launch rockets to the east as close to the equator as possible to reduce the apparent mass of the launch.

Given the uncertainty in calculating drop with drag, we often ignore the east/west apparent mass error but for long shots we need to include the small cross-range motion of the bullet. Most ballistic calculators include the cross range Coriolis correction. How do you know if yours does? If you need to enter in the Line of Fire (LOF) or direction that you are shooting and your latitude then your ballistic calculator can make the correction.

I hope this helps!

John Stutz, PhD
Aerospike Bullets, LLC
what post are you referring to, (previous post)
 
In a book about the Paris Gun, they said that the aiming point was six miles ahead of Paris. The projectile was in the air for 190 seconds. It was fired at an angle of 55 degrees. Other guns were fired at 45 degrees, but 55 got the projectile into the thin air of the Stratosphere that much faster. It was all really fascinating.
 
In a book about the Paris Gun, they said that the aiming point was six miles ahead of Paris. The projectile was in the air for 190 seconds. It was fired at an angle of 55 degrees. Other guns were fired at 45 degrees, but 55 got the projectile into the thin air of the Stratosphere that much faster. It was all really fascinating.
Oh, you are speaking my language! My dissertation was on space guns. After the Paris gun there was the V3 gun (like the V1 missile and the V2 rocket). It never went into service due to a big bombing campaign before D-Day, It would have launched shells from norther France into London. The next big one was the HARP gun that launched bullets into space. Two 16 inch battleship guns welded together. I used data from that gun.

For the big guns, full Coriolis is a must. A 20 mile 16 inch battleship gun from WW2 would be off by over a mile without Coriolis corrections.
 
W
Oh, you are speaking my language! My dissertation was on space guns. After the Paris gun there was the V3 gun (like the V1 missile and the V2 rocket). It never went into service due to a big bombing campaign before D-Day, It would have launched shells from norther France into London. The next big one was the HARP gun that launched bullets into space. Two 16 inch battleship guns welded together. I used data from that gun.

For the big guns, full Coriolis is a must. A 20 mile 16 inch battleship gun from WW2 would be off by over a mile without Coriolis corrections.

Was V3 the underground multi gun complex that would have fired shells into England at a crazy rate of fire?
 
W

Was V3 the underground multi gun complex that would have fired shells into England at a crazy rate of fire?
Yep. I did a pilgrimage to the gun site outside of Calais France to see it. It is a chalk mountain that was easy to dig out for the fix guns. The area around that mountain is the most bombed place on the face of the Earth.
 
Yes my solver has Corliolis correction. Shooter has a screen where you orientate the phone to the shooting direction and lock in the number. You go back to the main screen and calculate. Why don’t I use it? In practical hunting field instances it doesn’t mean squat. The correction is small compared to the environmentals (wind) in the field. It’s a matter of inches at 1K yards. It’s a distraction and time killer to mess with in the field with virtually no gain in a hunting situation. All in all interesting to know and understand but for me it doesn’t add value for what I use my solver for.
 
1K benchresters are sitting at a bench shooting in the same direction all day long so they would have no use for coriolis corrections. Wanna be snipers? Well maybe….depends on how far they are shooting and more importantly how well (accurately with precision) they can shoot and how accurately they can make wind calls. Pretty tall order
 
Here is how Bryan Litz of Applied Ballistics explains the Coriolis Effect in his Ballistics Books and Seminars. Bryan notes that Coriolis is “a very subtle effect. People like to make more of it than it is because it seems mysterious.” In most common shooting situations inside 1K, Coriolis is not important. At 1000 yards, the Effect represents less than one click (for most cartridge types). Even well past 1000 yards, in windy conditions, the Coriolis Effect may well be “lost in the noise”. But in very calm conditions, when shooting at extreme ranges, Bryan says you can benefit from adjusting your ballistics solution for Coriolis.

coriolis1502.gif
Bryan explains: “The Coriolis Effect… has to do with the spin of the earth. You are basically shooting from one point to another on a rotating sphere, in an inertial reference frame. The consequence of that is that, if the flight time of the bullet gets significantly long, the bullet can have an apparent drift from its intended target. The amount [of apparent drift] is very small — it depends on your latitude and azimuth of fire on the planet.”

SEE Daily Bulletin Article: https://bulletin.accurateshooter.co...ing-on-a-spinning-planet-the-coriolis-effect/

“Where you could think about Coriolis, and have it be a major impact on your hit percentage, is if you are shooting at extended range, at relatively small targets, in low-wind conditions. Where you know your muzzle velocity and BC very well, [and there are] pristine conditions, that’s where you’re going to see Coriolis creep in. You’ll receive more refinement and accuracy in your ballistics solutions if you account for Coriolis on those types of shots. But in most practical long-range shooting situations, Coriolis is NOT important. What IS important is to understand is when you should think about it and when you shouldn’t, i.e. when applying it will matter and when it won’t.”
 
Realistically, most people shooting the distances where it matters are using a ballistic solver. Just check the checkbox in your favorite program and let it apply the correction.

Spin Drift - Check
Coriolis Effect - Check

Then, move on to figuring out that switchy headwind that flips from 1 to 11 ...
 

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