Rich,
What you said makes perfect sense to me…at least intuitively. But, it would probably take a “lot†of testing with many different firearms to verify the perfect twist and velocity for various yardages.
The only point you mentioned I might take exception to is the weight of the bullet being a factor for stability, but with rimfire bullet shapes being almost identical…any increase in weight in most cases would increase the length and length is the primary factor for calculating projectile stability. So, in other words, I agree.
We can calculate stability by using this formula: Where Sg = Bullet stability Sg=,30*C5)/,,C7/C4)^2*C4^3*C6/C4*,1+,C6/C4)^2))*,C8/2800)^,1/3)*,,C9+460)/,59+460)*29.92/C10)
This formula was devised by Don Miller and is even endorsed by Bryan Litz as being very accurate, but when dealing with rimfires operating in the Mach 1 envelope…results can often be skewed by the smallest of variables. These variables would include the susceptibility of soft lead projectiles being deformed by the bore to a different shape and length. Something you normally wouldn’t have to account for in a jacketed bullet operating at supersonic velocities.
With these caveats predisposing truly accurate results, we can still estimate stability as an exercise in curiosity if you can give me an average for the length of the heel on a 22lr bullet. I didn’t want to pull any and can’t remember off the top of my head how far the heel of the bullet protrudes into the case.
I haven’t done this yet and I’m not aware of anyone else trying it on the many forums I lurk at. Your post has made me curious and it will only take me a few minutes to do some calculations with this formula because its embedded in a cell on an Excel spreadsheet and I can easily plug in the variables for twist, length, velocity, caliber, temperature, and pressure.