Tony, I often point this program out to people that automatically assume that a fatter barrel is stiffer than a smaller but shorter one..and sometimes it is, but not always.
In tuner design, I made a fixture that I can screw a bbl into, place a known weight at the muzzle, and measure actual deflection. It works but Dan Lilja put it into computer code and made it available to us as a part of his bbl weight calculator program.
I'll link it but first, it's good to read the details about it. Here's a link to the article. I suggest you read it before going straight to the program.
https://riflebarrels.com/a-look-at-the-rigidity-of-benchrest-barrels/
..and here's a link for it. I prefer the excel version. Use the BR bbl program. You can go in and modify bbl dimensions..such as changing from a 27" 1.250 straight to a 27" .900 straight. It can be frustrating at first but is very useful and telling, in regard to bbl droop. It might change your perspective about bbl stiffness, actual bbl droop amounts and why rf bbls aren't stiffer...err, bigger. Bottom line, a 27" 1.25 straight is
3.731 times stiffer than a 27" .900 straight.
https://riflebarrels.com/computer-software/
Another point, fwiw. I have a Pressure Trace system to measure relative chamber pressures and graph them out. They use a strain gage that measures the stretch of the bbl diameter and converts that to electricity. This provides a voltage that can be graphed on a computer screen. Over a 1.250 bbl shank, I can see the primer light off. Point being, bbls grow under pressure.
One more point. As the pressure falls, the bbl is stretched less. Hence, a natural choke in all bbls, to some degree. Not to mention, most rf tuners are clamped onto the muzzle, tensioning the bbl at the muzzle end and significantly reducing stretch, if not constricting the bore a bit.--Mike Ezell
Sorry, but I keep thinking of other points..
So, if we have .007052 deflection over 27" of .900 straight and lets say .250 of bearing surface, that's .0002611/inch divided by 4= roughly 65 millionths of and inch. The 1.250 will be 3.731 times less than THAT, of bullet deformation.
Or would it be less due to the area of the bore and it being more solid like, with that lead slug in it?
I think you get my point, regardless.
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