f class scoring

[kzin]

Right or wrong, I have never seen a tie broken using anything but "The Creedmoor Rule".. I have been shooting F-Class since 2011 and almost never miss a match.. I doubt very seriously if any other "method" has ever been used...

Yes, but what does that mean for the NEXT tie?

It should mean absolutely nothing, the correct, clear but tedious procedure is in the rulebook, not defined by precedent.

What it naturally tends to mean is "Every tie I've seen has been broken by Creedmoor so I'll do that." Most of the time it works out the same, the correct procedure would have got down to Creedmoor anyway, especially for high scoring ties on 3 equal length stages. It's also likely that occasionally a tie is broken incorrectly because of sloppy procedure.

 

[ShootDots]

Yes, but what does that mean for the NEXT tie?

It should mean absolutely nothing, the correct, clear but tedious procedure is in the rulebook, not defined by precedent.

What it naturally tends to mean is "Every tie I've seen has been broken by Creedmoor so I'll do that." Most of the time it works out the same, the correct procedure would have got down to Creedmoor anyway, especially for high scoring ties on 3 equal length stages. It's also likely that occasionally a tie is broken incorrectly because of sloppy procedure.

Okay..

 

[Nature Boy]

I thought the Creedmoor rule meant that if you’re shooting a Creedmoor and the other guy isn’t he might as well get back in the truck and go home because there’s no way for him to win.

 

[Rope2horns]

 

[Jetjock1]

I think something is being missed here. Look at the rules and consider what kind of a match you are considering. Let's assume it is and aggregate match. Write down the scores you are thinking about. Then apply the rules beginning at the top. Let me give you guys a problem. Two 600 yard mid range aggregates tied. 396-29xs. One shooter strings 198-15x & 198-14x. Second shooter 198-13x & 198-16x. Break the tie.

Answer: Can't be solved need the scorecard to see each shot value: Creedmoor: 15.4(c)(4)

Now Take the same scores but 1st string fired at 600 yards and second fired at 1000 yards. Break the tie.

Answer: 15.4(b)(2) breaks the tie, Shooter 2 wins 16X vs 14x.

Now One shooter strings 198-15x & 198-14x. Second shooter 198-15x & 198-14x. 1st shooter has 2-9s at 600 yards, 1-8 at 1000 yards; 2nd shooter has 2-9s at 600 yards 2-9s at 1000 yards. Break the tie.

Answer: 15.4(c)(2) Shooter 1 has 1-8 while shooter 2 has none, Shooter 2 wins no eights.

Jetjock

 

[Bob L.]

I think something is being missed here. Look at the rules and consider what kind of a match you are considering. Let's assume it is and aggregate match. Write down the scores you are thinking about. Then apply the rules beginning at the top. Let me give you guys a problem. Two 600 yard mid range aggregates tied. 396-29xs. One shooter strings 198-15x & 198-14x. Second shooter 198-13x & 198-16x. Break the tie.

Now Take the same scores but 1st string fired at 600 yards and second fired at 1000 yards. Break the tie.

Now One shooter strings 198-15x & 198-14x. Second shooter 198-15x & 198-14x. 1st shooter has 2-9s at 600 yards, 1-8 at 1000 yards; 2nd shooter has 2-9s at 600 yards 2-9s at 1000 yards. Break the tie.

Jetjock

I’ll try, if only to stimulate further conversation.
Taking scenario 2 first (600 & 1000 yd strings):

Shooters tie per Paragraph (b)
Using (c)(2), shooter 2 wins the 1000 yd string because he shot no 8’s while shooter 1 shot one 8.
At 600, shooters tie because both shot two 9’s.
Shooter 2 wins by virtue of winning the 1000 string

For scenario 1 (two 600 yd strings):

Applying paragraph (b), shooters tie per paragraph (b), since there is no longest range or next longest range. All shots are taken at 600 yds, so aggregate score still determines.
With no further information, none of Paragrsph (c) can be used. Need to know number of 9’s/8’s for (c) (2) to apply and individual shot scores in order for (c) (4) to apply.

Be gentle. I’m trying to learn.

 

[Snuggie]

^
You da man Bob!

 

[Jetjock1]

I’ll try, if only to stimulate further conversation.
Taking scenario 2 first (600 & 1000 yd strings):

Shooters tie per Paragraph (b)
Using (c)(2), shooter 2 wins the 1000 yd string because he shot no 8’s while shooter 1 shot one 8.
At 600, shooters tie because both shot two 9’s.
Shooter 2 wins by virtue of winning the 1000 string

For scenario 1 (two 600 yd strings):

Applying paragraph (b), shooters tie per paragraph (b), since there is no longest range or next longest range. All shots are taken at 600 yds, so aggregate score still determines.
With no further information, none of Paragrsph (c) can be used. Need to know number of 9’s/8’s for (c) (2) to apply and individual shot scores in order for (c) (4) to apply.

Be gentle. I’m trying to learn.

Read the post again, there are not any individual matches, they are AGGREGATES. Youmust solve the ties on that basis. You are analyzing the scores as individual not aggregates. Try again.
Jetjock

 

[Bob L.]

Read the post again, there are not any individual matches, they are AGGREGATES. Youmust solve the ties on that basis. You are analyzing the scores as individual not aggregates. Try again.
Jetjock

I see what you mean after reading your post #25.
I think I’ll retire early from scoring and just shoot. It’s more fun.